3p^2-20p=7

Solution for 3p^2-20p=7 equation:

3p^2-20p=7

We move all terms to the left:

3p^2-20p-(7)=0

a = 3; b = -20; c = -7;
Δ = b2-4ac
Δ = -202-4·3·(-7)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-22}{2*3}=\frac{-2}{6}
=-1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+22}{2*3}=\frac{42}{6}
=7
$